AndyKent
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Registered: 3rd Sep 05
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I'm doing an assignment for my surveying degree and its doing my head in. Anyone know where I even start?
A 2.4m long by 62.5mm diameter solid steel circular column supports an axial force of 900kN, as shown in Diagram 4. The column is supported at the centre of a 675mm square by a 2.1m high brickwork pier, which itself is supported at the centre of a 2m square by 0.9m deep reinforced concrete foundation.
Help, doing my head in.
This is only one question of four as well 
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Fonz
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Registered: 12th May 06
Location: Newbury, Berks
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you've not stated what your question is, only the facts as shown by the diagram....what is the question asking you to calculate?
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Liamjohnson_05
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Registered: 10th Jun 08
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Should have listened in class you fucking DOUCHE!
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AK
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Registered: 5th Jul 00
Location: Aberdeen City
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and the question is 
I'm not a structural engineer, but i'm doing an engineering degree just now 
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AndyKent
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Registered: 3rd Sep 05
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Oh fuck, what a tit.
i. Determine the maximum compression stress developed within each material.
ii. If the modulus of elasticity of the steel in the column is 205kN/mm², calculate the change in the steel column’s length under the load.
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jrsteeve
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Registered: 3rd Apr 02
Location: Manchester
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I'm doing building surveying too but am in 3rd year of 5, part time. Don't know the answer but have a look at the metric handbook, usually some helpful equations in there.
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AK
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Registered: 5th Jul 00
Location: Aberdeen City
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E = Stress / Strain
stress = force / area = 900,000N / 3068 = 293.4
strain = stress / E = 293.4 / 205000N = 0.0143
Change in L = strain * L = 0.0143 * 2400 = 3.4mm
so change in length is 3.4mm
maybe sounds wrong to me
[Edited on 22-02-2011 by AK]
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Nath
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Registered: 3rd Apr 02
Location: MK
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quote:
Originally posted by Liamjohnson_05
Should have listened in class you fucking DOUCHE!
Pleasant fellow.
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AK
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Registered: 5th Jul 00
Location: Aberdeen City
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streel - 293.4
brick - 1.98
base - 0.225
just rough using F/A
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AndyKent
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Registered: 3rd Sep 05
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quote:
Originally posted by AK
E = Stress / Strain
stress = force / area = 900,000N / 3068 = 293.4
strain = stress / E = 293.4 / 205000N = 0.0143
Change in L = strain * L = 0.0143 * 2400 = 3.4mm
so change in length is 3.4mm
maybe sounds wrong to me
[Edited on 22-02-2011 by AK]
Might be right. The tutor posted some hints which include most of what you've said. They make much more sense with some figures applied
What about part 1 
edit, you're one step ahead of me.
[Edited on 22-02-2011 by AndyKent]
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AK
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Registered: 5th Jul 00
Location: Aberdeen City
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see post above with simple stress calculations (stress = force/area)
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AndyKent
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Registered: 3rd Sep 05
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Ah, right, got it now. Your figure of 3068 confused me until I realised thats pie * r squared for the base of the column.
Awesome, thanks 
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