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Author Any structural engineers?
AndyKent
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Registered: 3rd Sep 05
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22nd Feb 11 at 17:18   View User's Profile U2U Member Reply With Quote
I'm doing an assignment for my surveying degree and its doing my head in. Anyone know where I even start?

A 2.4m long by 62.5mm diameter solid steel circular column supports an axial force of 900kN, as shown in Diagram 4. The column is supported at the centre of a 675mm square by a 2.1m high brickwork pier, which itself is supported at the centre of a 2m square by 0.9m deep reinforced concrete foundation.



Help, doing my head in.

This is only one question of four as well
Fonz
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22nd Feb 11 at 17:29   View Garage View User's Profile U2U Member Reply With Quote
you've not stated what your question is, only the facts as shown by the diagram....what is the question asking you to calculate?
Liamjohnson_05
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22nd Feb 11 at 17:35   View User's Profile U2U Member Reply With Quote
Should have listened in class you fucking DOUCHE!
AK
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22nd Feb 11 at 17:37   View User's Profile U2U Member Reply With Quote
and the question is

I'm not a structural engineer, but i'm doing an engineering degree just now
AndyKent
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22nd Feb 11 at 17:43   View User's Profile U2U Member Reply With Quote
Oh fuck, what a tit.

i. Determine the maximum compression stress developed within each material.

ii. If the modulus of elasticity of the steel in the column is 205kN/mm², calculate the change in the steel column’s length under the load.
jrsteeve
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22nd Feb 11 at 18:05   View User's Profile U2U Member Reply With Quote
I'm doing building surveying too but am in 3rd year of 5, part time. Don't know the answer but have a look at the metric handbook, usually some helpful equations in there.
AK
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22nd Feb 11 at 18:05   View User's Profile U2U Member Reply With Quote
E = Stress / Strain

stress = force / area = 900,000N / 3068 = 293.4

strain = stress / E = 293.4 / 205000N = 0.0143

Change in L = strain * L = 0.0143 * 2400 = 3.4mm

so change in length is 3.4mm

maybe sounds wrong to me

[Edited on 22-02-2011 by AK]
Nath
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22nd Feb 11 at 18:06   View User's Profile U2U Member Reply With Quote
quote:
Originally posted by Liamjohnson_05
Should have listened in class you fucking DOUCHE!


Pleasant fellow.
AK
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22nd Feb 11 at 18:13   View User's Profile U2U Member Reply With Quote
streel - 293.4
brick - 1.98
base - 0.225

just rough using F/A
AndyKent
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22nd Feb 11 at 18:16   View User's Profile U2U Member Reply With Quote
quote:
Originally posted by AK
E = Stress / Strain

stress = force / area = 900,000N / 3068 = 293.4

strain = stress / E = 293.4 / 205000N = 0.0143

Change in L = strain * L = 0.0143 * 2400 = 3.4mm

so change in length is 3.4mm

maybe sounds wrong to me

[Edited on 22-02-2011 by AK]


Might be right. The tutor posted some hints which include most of what you've said. They make much more sense with some figures applied

What about part 1

edit, you're one step ahead of me.

[Edited on 22-02-2011 by AndyKent]
AK
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22nd Feb 11 at 18:16   View User's Profile U2U Member Reply With Quote
see post above with simple stress calculations (stress = force/area)
AndyKent
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22nd Feb 11 at 19:17   View User's Profile U2U Member Reply With Quote
Ah, right, got it now. Your figure of 3068 confused me until I realised thats pie * r squared for the base of the column.

Awesome, thanks

 
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